嵌套序列化在 C#

Question

我被要求按以下格式提供 json 中的數據：

{
    "testsystem": "1.0.0",
    "playback": { 
       "1": {
          "cue": 1,
          "state": "Stopped",
          "label": "Hello"
       },
       "2": {
          "cue": 100,
          "state": "Running",
          "label": "Hello"
       }
    }
}

我一直在使用 Newtonsoft json 來序列化信息，但有幾點讓我感到困惑。

public class Company
        {
            [JsonProperty("testsystem")]
            public string testsystem { get; set; }

            [JsonProperty("playback")]
            public pb playback { get; set; }

        }

        public class pb
        {
            [JsonProperty("playback")]
            public int playback { get; set; }

            //[JsonProperty("cue")]
            public cue cue { get; set; }
        }


        public class cue
        {
            [JsonProperty("cue")]
            public string number { get; set; }

            [JsonProperty("state")]
            public string state { get; set; }

            [JsonProperty("label")]
            public string label { get; set; }

        }

我的 class 報關單

Company thisCompany = new Company
{
    testsystem = "1.0.0",
    for (PB = 1; PB < 7; PB++)
    {
       playback = new pb
       {
           cue = new cue
           {
           number = Globals.QNumber[1],                             
           state = Globals.QState[1],
           label = Globals.QLabel[1]                             
           }
       }
}
string json = JsonConvert.SerializeObject(thisCompany);

我試圖序列化的代碼部分

所以我的第一個問題是我無法弄清楚如何嵌套“播放”部分，以便在示例中有 2 個。 我嘗試添加一個 for 循環但是（如我上面的代碼所示）但這似乎使 playback = new pb 行脫離了上下文？

第二個問題是我在下面的 output 中顯示了一個雙“播放部分”

{
  "testsystem": "1.0.0",
  "playback": {
    "playback": 0,
    "cue": {
      "cue": "34",
      "state": "Running",
      "label": "Hello World"
    }
  }
}

我覺得這一定很簡單，但我只是錯過了最簡單的事情和想得太多。 提前感謝您的任何想法和建議。

Answer 1

我認為您的 model 不太適合示例 json。您的“播放”object 是一本字典，它應該看起來更像這樣：

public class Company
{
    [JsonProperty("testsystem")]
    public string Testsystem { get; set; }

    [JsonProperty("playback")]
    public Dictionary<string, Playback> Playback { get; set; }
}

public class Playback
{
    [JsonProperty("cue")]
    public int Cue { get; set; }

    [JsonProperty("state")]
    public string State { get; set; }

    [JsonProperty("label")]
    public string Label { get; set; }
}

然后你可以創建 object 並像這樣序列化它們：

public static string CreateCompanyJson()
{
    var thisCompany = new Company
    {
        Testsystem = "1.0.0",
        Playback = new Dictionary<string, Playback>()
    };
    for (var pb = 1; pb < 7; pb++)
    {
        thisCompany.Playback[$"{pb}"] = new Playback
        {
            Cue = pb,
            State = $"State-{pb}",
            Label = $"Label-{pb}"
        };
    }
     return JsonConvert.SerializeObject(thisCompany, Formatting.Indented);
}

這將生成格式類似於您的示例的 json：

{
  "testsystem": "1.0.0",
  "playback": {
    "1": {
      "cue": 1,
      "state": "State-1",
      "label": "Label-1"
    },
    "2": {
      "cue": 2,
      "state": "State-2",
      "label": "Label-2"
    },
    "3": {
      "cue": 3,
      "state": "State-3",
      "label": "Label-3"
    },
    "4": {
      "cue": 4,
      "state": "State-4",
      "label": "Label-4"
    },
    "5": {
      "cue": 5,
      "state": "State-5",
      "label": "Label-5"
    },
    "6": {
      "cue": 6,
      "state": "State-6",
      "label": "Label-6"
    }
  }
}

Answer 2

如果你只需要一個 json 字符串，你不需要任何類

    var company = new JObject
    {
        ["testsystem"] = "1.0.0",
        ["playback"] = new JObject()
    };
    for (var pb = 1; pb < 7; pb++)
    {
        ((JObject)company["playback"]).Add(
        CreateJsonProperty(pb.ToString(), pb * 10, $"state{pb}", $"label{pb}")
        );
    }

    var json = company.ToString();

public static JProperty CreateJsonProperty(string pb, int cue, string state, string label)
{
    return new JProperty(pb, new JObject
    {
        ["cue"] = cue,
        ["state"] = state,
        ["label"] = label
    });
}