[英]How to extract the first non-Null match from a group of regexp matches in Python?
假設我有一個正則表達式(a)|(b)|(c)|(d)
。 如果我將其應用於文本'foobar'
則會得到一個匹配對象
>>> compiled = re.compile('(a)|(b)|(c)|(d)')
>>> compiled.search('foobar').groups()
(None, 'b', None, None)
如何從此處提取'b'
? 還是一般來說,如何從未知數量的組中提取第一個匹配項(當動態創建正則表達式時會發生這種情況)?
>>> g = (None, 'b', None, None)
>>> next(x for x in g if x is not None)
'b'
>>> g = (None, None, None)
>>> next((x for x in g if x is not None), "default") # try this with filter :)
'default'
>>> g = (None, None, None) # so you know what happens, and what you could catch
>>> next(x for x in g if x is not None)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
StopIteration
reduce(lambda x, y : (x, y)[x is None], groups, None)
filter(lambda x : x is not None, groups)[0]
>>> g = (None,'b',None,None)
>>> filter(None,g)
('b',)
>>> h = (None,None,None)
>>> filter(None,h)
()
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