如果旋轉超過45度，為什么旋轉不起作用

Question

我正在嘗試在軸上旋轉波浪，但是以某種方式，如果我傳遞到正弦值並將cos值設置為大於45，則波浪似乎會變形或函數無法以適當的角度旋轉。

...
wave

// ROtate 
for (int i=0; i<300; i++){
    coordinatesX[i] = ((coordinatesX[i] * (float)Math.cos(60)) - (coordinatesY[i] * (float)Math.sin(60))) + coordinatesX[i];
    coordinatesY[i] = (coordinatesX[i] * (float)Math.sin(60)) + (coordinatesY[i] * (float)Math.cos(60)) + coordinatesY[i];
}

這是整個代碼：

// define newpath
float[] coordinatesX = new float[300]; 
float[] coordinatesY = new float[300];
// wave
for (int i=0; i<300; i++){
    coordinatesX[i] =  i;
    coordinatesY[i] = (float)(20 * (Math.sin((-0.10 * coordinatesX[i]))));
    System.out.println(coordinatesX[i]);
    System.out.println(coordinatesY[i]);
}


// ROtate 
for (int i=0; i<300; i++){
    coordinatesX[i] = ((coordinatesX[i] * (float)Math.cos(-10)) - (coordinatesY[i] * (float)Math.sin(-10))) + coordinatesX[i];
    coordinatesY[i] = (coordinatesX[i] * (float)Math.sin(-10)) + (coordinatesY[i] * (float)Math.cos(-10)) + coordinatesY[i];
}

// Translate 
for (int i=0; i < 300; i++) {
    coordinatesX[i] = coordinatesX[i]+ (200);
    coordinatesY[i] = coordinatesY[i] + (300);
}

Answer 1

您的代碼尚不清楚您到底要做什么，但是您提到了45度

Math.sin()和Math.cos()使用弧度http://docs.oracle.com/javase/1.4.2/docs/api/java/lang/Math.html