HttpWebRequest Post方法發送部分數據

Question

我有以下代碼向服務器發送POST請求。

HttpWebRequest myWebRequest = (HttpWebRequest)HttpWebRequest.Create(uri);
myWebRequest.Method = WebRequestMethods.Http.Post;
myWebRequest.ContentLength = data.Length;
myWebRequest.ContentType = "application/x-www-form-urlencoded";
StreamWriter writer = new StreamWriter(myWebRequest.GetRequestStream());
writer.Write(data);
writer.Close();

要發布的數據是一個包含近2000個字符的XML請求。 我閱讀了如下所示的回復。

this.Response.ContentType = "text/xml";
StreamReader reader = new StreamReader(this.Request.InputStream);
string responseData = reader.ReadToEnd();

我們上面獲得的響應數據只發送了一部分實際數據。

請幫我獲取完整的數據。

Answer 1

這對我有用，我想你錯過了編碼...使用這個我正在向服務器發送巨大的xml

        HttpWebRequest request = (HttpWebRequest)WebRequest.Create(connectionString);
        request.ContentType = "application/x-www-form-urlencoded";
        request.Method = "POST";
        byte[] byteArray = Encoding.UTF8.GetBytes(postData);
        // Set the ContentType property of the WebRequest.
        // Set the ContentLength property of the WebRequest.
        request.ContentLength = byteArray.Length;
        // Get the request stream.
        Stream dataStream = request.GetRequestStream();
        // Write the data to the request stream.
        dataStream.Write(byteArray, 0, byteArray.Length);
        // Close the Stream object.
        dataStream.Close();
        WebResponse response = request.GetResponse();
        //Console.WriteLine("Service Status Code:"+((HttpWebResponse)response).StatusDescription);
        // Get the stream containing content returned by the server.
        dataStream = response.GetResponseStream();
        // Open the stream using a StreamReader for easy access.
        StreamReader reader = new StreamReader(dataStream);
        // Read the content.
        string responseFromServer = reader.ReadToEnd();

Answer 2

我一直這樣做的方式與你的方式略有不同：

HttpWebRequest request = (HttpWebRequest)HttpWebRequest.Create(URL);
request.Method = WebRequestMethods.Http.Post;
request.ContentLength = DataToPost.Length;
request.ContentType = "application/x-www-form-urlencoded";
StreamWriter writer = new StreamWriter(request.GetRequestStream());
writer.Write(DataToPost);
writer.Close();
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
StreamReader reader = new StreamReader(response.GetResponseStream());

這種方式已經工作多年了。