cython / numpy類型的數組

Question

我正在嘗試構造python類型int（64位帶符號整數）的矩陣。

cdef matrix33():
    return np.zeros((3,3),dtype=int)

cdef do_stuf(np.ndarray[int, ndim=2] matrix):
    ...
    return some_value

def start():
    print do_stuf(matrix33())

它編譯正確，但是當我運行它時，我不斷收到此錯誤：

ValueError: Buffer dtype mismatch, expected 'int' but got 'long'

我無法使用python long的，但我不知道如何正確轉換為64 int。

更新

好。 我確信我正確使用了Cython。 我編寫的代碼是用於Capture Go / Atari Go游戲中的minmax搜索。

到目前為止，最常用的功能是：

cdef isThere_greedy_move(np.ndarray[np.int64_t, ndim=2]board, int player):
    cdef int i, j
    for i in xrange(len(board)):
        for j in xrange(len(board)):
            if board[i,j] == 0:
                board[i,j] = player
                if player in score(board):
                    board[i,j] = 0
                    return True
                board[i,j] = 0
    return False


# main function of the scoring system.
# returns list of players that eat a stone
cdef score(np.ndarray[np.int64_t, ndim=2] board):
    scores = []
    cdef int i,j
    cdef np.ndarray[np.int64_t, ndim = 2] checked
    checked = np.zeros((board.shape[0], board.shape[1]), dtype = int)
    for i in xrange(len(board)):
        for j in xrange(len(board)):
            if checked[i,j] == 0 and board[i,j] !=0:
                life, newly_checked = check_life(i,j,board,[])
                if not life:
                    if -board[i,j] not in scores:
                        scores.append(-board[i,j])
                        if len(scores) == 2:
                            return scores
                checked = update_checked(checked, newly_checked)
    return scores

# helper functions of score/1
cdef check_life(int i, int j, np.ndarray[np.int64_t, ndim=2] board, checked):
    checked.append((i,j))
    if liberty(i,j,board):
        return True, checked
    for pos in [[1,0],[0,1],[-1,0],[0,-1]]:
        pos = np.array([i,j]) + np.array(pos)
        if check_index(pos[0],pos[1],len(board)) and board[pos[0],pos[1]] == board[i,j] and (pos[0],pos[1]) not in checked:
            life, newly_checked = check_life(pos[0],pos[1],board,checked)
            if life:
                checked = checked + newly_checked             
                return life, checked
    return False, []    # [] is a dummy.

cdef liberty(int i,int j, np.ndarray[np.int64_t, ndim=2] board):
    for pos in [np.array([1,0]),np.array([0,1]),np.array([-1,0]),np.array([0,-1])]:
        pos = np.array([i,j]) - pos
        if check_index(pos[0],pos[1],len(board)) and board[pos[0],pos[1]] == 0:
            return True
    return False

我真的以為這將是一個為賽昂大放異彩的機會。 要解決3x3捕獲，請執行以下操作：

Python 2.7的一致性為2.28秒，而cython的一致性為2.03秒兩者均在python time模塊和低於60°C的i7處理器上進行了測試

現在對我來說，問題是我是否要為此項目切換到Haskell或C ++ ...

Answer 1

Cython的int類型與C int相同，即通常（但不一定）為32位。 你應該申報dtype在matrix33作為np.int64和do_stuf為相應的C， np.int64_t ：

cimport numpy as np
import numpy as np

cdef do_stuff(np.ndarray[np.int64_t, ndim=2] matrix):
    pass

cdef matrix33():
    return np.zeros((3,3), dtype=int)

def start():
    print do_stuff(matrix33())