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回發后如何執行按鈕單擊以打開模式窗口

[英]How to perform a button click after a postback to open a modal window

我在使按鈕在回發后執行點擊時遇到麻煩。 我正在驗證網頁上的模式窗口內的一些文本框,該文本框僅在單擊按鈕后出現。 當前,在回發之后,網頁將重新打開,並且模式窗口已關閉,需要打開該窗口。 我的代碼中沒有處理程序,單擊該按鈕並運行html代碼以打開模式窗口。 一旦我發回郵件,就需要單擊此按鈕,以便啟動驗證。 我嘗試使用btnSickness.Click(),但它似乎不喜歡這種方法,而且似乎在任何地方都找不到! 碼:

public partial class _Default : System.Web.UI.Page
{

    int i = 0;

    protected void Page_Load(object sender, EventArgs e)
    {
        if (i > 0)
           {
           }      

    }

    protected void chkDoctor_SelectedIndexChanged(object sender, EventArgs e)
    {
        if (drpDoctor.SelectedValue == "Yes")
        {
            txtIfNoWhy.ReadOnly = true;
            txtIfNoWhy.BackColor = Color.LightGray;
            i++;
        }
        else if (drpDoctor.SelectedValue == "No")
        {
            txtDocName.ReadOnly = true;
            txtHouseName.ReadOnly = true;
            txtStreet.ReadOnly = true;
            txtTownCity.ReadOnly = true;
            txtCounty.ReadOnly = true;
            txtPostalcode.ReadOnly = true;
            txtInitialDate.ReadOnly = true;
            txtTreatmentRecieved.ReadOnly = true;
            txtCurrentTreatment.ReadOnly = true;

            txtDocName.BackColor = Color.LightGray;
            txtHouseName.BackColor = Color.LightGray;
            txtStreet.BackColor = Color.LightGray;
            txtTownCity.BackColor = Color.LightGray;
            txtCounty.BackColor = Color.LightGray;
            txtPostalcode.BackColor = Color.LightGray;
            txtInitialDate.BackColor = Color.LightGray;
            txtTreatmentRecieved.BackColor = Color.LightGray;
            txtCurrentTreatment.BackColor = Color.LightGray;
            i++;
        }
    }
}

模態窗口代碼:

<div class"modal" id="myModal"></div> 
    <div class="row-fluid">
        <div class="span2">
                <asp:Button runat="server" class="btn" data-toggle="modal" href="#Div1" ID="btnSickness" Text="Submit a Sickness Form" />
                       <div class="modal hide" id="Div1">
<div class="modal-header">
<button class="close" data-dismiss="modal">×</button>
<h3>Sickness Form</h3>
</div>
<div class="modal-body">
<p>Please fill in the following information regarding your sickness</p>
<br />
<p>Sickness Date From:</p>
<asp:TextBox runat="server" ID="txtSicknessFrom"></asp:TextBox>
<br />
<p>Sickness Date To:</p>
<asp:TextBox runat="server" ID="txtSicknessTo"></asp:TextBox>
    <br />
<p>Absence Date To:</p>
<asp:TextBox runat="server" ID="txtAbsenceFrom"></asp:TextBox>

您可以設置一個隱藏字段,告訴模態從服務器返回時顯示。 然后,您可以添加一個pageLoad javascript函數,該函數在每次pageLoad時運行,以檢查是否需要顯示模式。

服務器端

hdf_ShowModal.Value = "true";

HTML

<asp:HiddenField runat="server" ID="hdf_ShowModal" />

Javascript

function pageLoad(sender, args)
{
    if(document.getElementById('<%= hdf_ShowModal.ClientID %>').value == "true")
    {
        // perform code to show modal
    }
}

編輯

由於還使用了jquery,因此可以嘗試以下操作來顯示模式:

function pageLoad(sender, args)
{
    if($('[id$=hdf_ShowModal]').val() == "true")
        $('#myModal').modal({ show: true });
}

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