[英]SQL: join two tables (LEFT OUTER JOIN) then update values
我試圖根據另一張表中的值更新一列中的值。
如果列都在同一表中,則可以執行以下操作:
UPDATE wp_posts
SET post_date = REPLACE (post_date, 'X', 'Y')
WHERE meta_value = 'Z';
但是我需要先連接兩個表才能進行更新:
SELECT *
FROM wp_posts
LEFT OUTER JOIN wp_postmeta ON post_id = post_id
如何根據已加入的兩個表進行更新?
如果您使用SQL Server ,請嘗試這種方式
UPDATE WP
SET WP.post_date = REPLACE(WPM.post_date, 'X', 'Y')
FROM wp_posts WP
LEFT OUTER JOIN wp_postmeta WPM ON WP.post_id = WPM.post_id
WHERE WP.meta_value = 'Z';
更新:
如果您使用的是MySQL 。 這是MySQL更新
UPDATE wp_posts WP
LEFT JOIN wp_postmeta WPM ON WP.post_id = WPM.post_id
SET WP.post_date = REPLACE(WPM.post_date, 'X', 'Y')
WHERE meta_value = 'Z';
SQL服務器
UPDATE wp_posts
post_date = REPLACE (post_date, 'X', 'Y')
FROM wp_posts WP LEFT OUTER JOIN wp_postmeta WPM ON WP.post_id = WPM.post_id
WHERE meta_value = 'Z';
MySQL的
UPDATE wp_posts
LEFT JOIN wp_postmeta WPM ON WP.post_id = WPM.post_id
SET post_date = REPLACE (post_date, 'X', 'Y')
WHERE meta_value = 'Z'
UPDATE wp_posts SET post_date = REPLACE (WPM.post_date, 'X', 'Y')
FROM wp_posts AS WP
LEFT OUTER JOIN wp_postmeta AS WPM ON WP.post_id = WPM.post_id
WHERE WP.meta_value = 'Z'
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