[英]WCF Service not Processing MSMQ Message
我有一個WCF Windows服務,用於檢查MSMQ消息。 它可以正常接收消息,但似乎未調用ProcessMSMQMessage事件。
任何想法為什么會這樣? 我是否正確設置了ProcessMSMQMessage事件? 還是我錯過了什么?
我的代碼如下。 謝謝。
WCF服務類別...
public partial class MyService : ServiceBase
{
private ServiceHost host;
public MyService()
{
InitializeComponent();
}
protected override void OnStart(string[] args)
{
string queueName = ConfigurationManager.AppSettings["ProcessMsgQueueName"];
if (!MessageQueue.Exists(queueName))
{
MessageQueue thisQueue = MessageQueue.Create(queueName, true);
thisQueue.SetPermissions("Everyone", MessageQueueAccessRights.ReceiveMessage);
}
try
{
Uri serviceUri = new Uri("msmq.formatname:DIRECT=OS:" + queueName);
// communicate to MSMQ how to transfer and deliver the messages
MsmqIntegrationBinding serviceBinding = new MsmqIntegrationBinding();
serviceBinding.Security.Transport.MsmqAuthenticationMode = MsmqAuthenticationMode.None;
serviceBinding.Security.Transport.MsmqProtectionLevel = System.Net.Security.ProtectionLevel.None;
serviceBinding.SerializationFormat = MsmqMessageSerializationFormat.Binary;
host = new ServiceHost(typeof(MyService.Service1)); // add watcher class name
host.AddServiceEndpoint(typeof(MyService.IService1), serviceBinding, serviceUri);
host.Open();
}
catch (Exception ex)
{
EventLog.WriteEntry("SERVICE" + ex.Message, EventLogEntryType.Error);
}
}
protected override void OnStop()
{
if (host != null)
host.Close();
}
}
IService1合同...
[ServiceContract(Namespace = "MyService")]
[ServiceKnownType(typeof(Events.Dashboard_Message))]
public interface IService1
{
[OperationContract(IsOneWay = true)]
void ProcessMSMQMessage(MsmqMessage<Events.Dashboard_Message> msg);
}
Service1類...
public class Service1 : IService1
{
[OperationBehavior(TransactionScopeRequired = true, TransactionAutoComplete = true)]
public void ProcessMSMQMessage(MsmqMessage<Events.Dashboard_Message> msg)
{
string msgName = msg.GetType().Name;
// send to eventlog
EventLog.WriteEntry("MyService", msgName);
}
}
終於成功了。
問題出在IService1合同中。 需要添加Action = "*"
。
[OperationContract(IsOneWay = true, Action = "*")]
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.