來自C＃中數據集的foreach循環中的XML

Question

我必須在C＃中動態創建一個非常特定的形狀XML文件，以便為網站上的flash對象提供動力。 我在許多嘗試中遇到的問題是，大多數輸出​​都希望每個節點都有某種獨特的識別方式，我不希望這樣。 相反，下面是我要追求的輸出，而不是我目前可以獲得的輸出。 請注意，它也是無效的XML。

<data>
    <Annual Enrollment>
        <row>
            <column>value1</column>
            <column>value2</column>
            <column>value3</column>
        </row>
        <row>
            <column>value1</column>
            <column>value2</column>
            <column>value3</column>
        </row>
    </Annual Enrollment>
    <Pre-College>
        <row>
            <column>value1</column>
            <column>value2</column>
            <column>value3</column>
        </row>
        <row>
            <column>value1</column>
            <column>value2</column>
            <column>value3</column>
        </row>
    </Pre-College>

......等等。 節點標題或者不能更改，也不能為每棵樹的根目錄。

到目前為止我的代碼看起來像這樣，在我看來它似乎應該工作，但事實並非如此。

  var tableResult = DashboardData.GetMetricData(1);
  // Outlinining structure
  XDocument document = new XDocument(
       new XDeclaration("1.0", "utf-8", null),
       new XElement("data",
            new XElement("AnnualEnrollment"),
            new XElement("Pre-College"),
            new XElement("Summary")
            ));
  // Now I need to append children to each of the three nodes within the root "data"
  foreach (DataRow row in tableResult.Tables[0].Rows)
  {
      document.Element("AnnualEnrollment").Add(new XElement("row"));

      foreach (var item in row.ItemArray)
      {
          var element = new XElement("column", item);


      }
  }

Answer 1

考慮使用XmlWriter獲得更多控制和靈活的文檔結構

var docBuilder = new StringBuilder();
using (var writer = XmlWriter.Create(docBuilder))
{
    writer.WriteStartElement("data");
    writer.WriteStartElement("AnnualEnrollment");
    foreach (var row in dataTable.Rows)
    {
        writer.WriteStartElement("row");
        foreach (var item in row.ItemArray)
            writer.WriteElementString("column", item);
        writer.WriteEndElement(); // row
    }
    writer.WriteEndElement(); // Annual Enrollment
    writer.WriteEndElement(); // data
}
docBuilder.Replace("<AnnualEnrollment>", "<Annual Enrollment>");

Answer 2

我希望它看起來更像這樣：

  foreach (DataRow row in tableResult.Tables[0].Rows)
  {
     XElement aRow = new XElement("row")

     foreach (var item in row.ItemArray)
     {
          aRow.Add(new XElement("column", item))
     }

     document.Element("AnnualEnrollment").Add(aRow);

  }

Answer 3

下面的示例從第一個表讀取行並將它們轉換為行元素，提供轉換為列元素的內容列值。

XDocument document = new XDocument(
    new XDeclaration("1.0", "utf-8", null),
    new XElement("data",
        new XElement("AnnualEnrollment", 
            from row in tableResult.Tables[0].AsEnumerable()
            select new XElement("row", 
                from column in tableResult.Tables[0].Columns.Cast<DataColumn>()
                select new XElement("column", row[column]))),
        new XElement("Pre-College"), // same for pre-college table
        new XElement("Summary") // and same for summary
        ));

我還將DataTable轉換為單獨的（擴展）方法：

public static object ToXml(this DataTable dataTable)
{
    return from row in dataTable.AsEnumerable()
           select new XElement("row",
                      from column in dataTable.Columns.Cast<DataColumn>()
                      select new XElement("column", row[column]));
}

現在您的Xml生成將如下所示：

XDocument document = new XDocument(
    new XDeclaration("1.0", "utf-8", null),
    new XElement("data",
        new XElement("AnnualEnrollment", tableResult.Tables[0].ToXml()),
        new XElement("Pre-College", tableResult.Tables[1].ToXml()),
        new XElement("Summary", tableResult.Tables[2].ToXml()) 
        ));