從資源文件/內容獲取流

Question

這是從資源文件獲取流的正確/唯一方法嗎？

    Uri uri = new Uri(fullPath);

    StorageFile storageFile = 
      await Windows.Storage.StorageFile.
        GetFileFromApplicationUriAsync(uri);

    IRandomAccessStreamWithContentType randomAccessStream = 
      await storageFile.OpenReadAsync();

    IInputStream resourceStream = (IInputStream)
      randomAccessStream.GetInputStreamAt(0);

我所有其他來源（http和本地存儲）都返回一個Stream對象，不得不使用一個或另一個的if-else代碼很痛苦。

我也嘗試過用它創建一個MemoryStream，但是我什至找不到一種方法來取出字節...請幫助。

    uint size = (uint)randomAccessStream.Size;
    IBuffer buffer = new Windows.Storage.Streams.Buffer(size);
    await randomAccessStream.ReadAsync(buffer, size, 
      InputStreamOptions.None);

    Stream stream = new MemoryStream(buffer); // error takes byte[] not IBuffer

從資源讀取時的IInputStream.ReadAsync（）： http : //msdn.microsoft.com/zh-cn/library/windows/apps/windows.storage.streams.iinputstream.readasync.aspx

而Stream.Read（）和Stream.ReadAsync（）看起來像這樣：

http://msdn.microsoft.com/en-us/library/system.io.stream.read.aspx

和

http://msdn.microsoft.com/en-us/library/hh137813.aspx

謝謝

Answer 1

好吧，我找到了！

    StorageFile storageFile =
      await Windows.Storage.StorageFile.GetFileFromApplicationUriAsync(uri);

    var randomAccessStream = await storageFile.OpenReadAsync();
    Stream stream = randomAccessStream.AsStreamForRead();

Answer 2

您也可以減少一行：

Stream stream = await storageFile.OpenStreamForReadAsync();