用ILnumerics和c＃绘制3d表面

Question

I have used this code:

    private void ilPanel1_Load(object sender, EventArgs e)
    {    using (ILScope.Enter())
        {
            ILArray<float> X = new float[] { 0, 0, 1, 1, 2.5F, -2.6F, 5, 9, 1, 38 };
            ILArray<float> Y = new float[] { 1, 0, 1, 0, 1.5F,  0.5F, 5, 9, 1, 39 };
            ILArray<float> Z = new float[] { 0, 0, 1, 1, 0.4F, -0.2F, 5, 9, 1, 39 };
            X = X.Reshape(2,5);
            Y = Y.Reshape(2,5);
            Z = Z.Reshape(2,5);
            ilPanel1.Scene.Add(new ILPlotCube(twoDMode: false) {
                new ILSurface(Z, colormap: Colormaps.Cool) {
                    Colors = 1.4f  ,Children = { new ILColorbar() }
                }
            });
        }
    }

This produces:

However I checked this question and tried to adapt deprecated ILnumerics solution (as I did not find other c# code), but still do not get it, every coordinate (Z,X and Y) corresponds to one slice (mxn) in the array. So it is necesarry to reshape data.

this part is the problem:

            X = X.Reshape(2,5);
            Y = Y.Reshape(2,5);
            Z = Z.Reshape(2,5);

If I do not give correct size, program fails, so in example I have 10 elements on each vector, so when resahping I would put 2,5 which multiplied are 10?...

What about case I have 11 elements as if I put 2,5 on reshape I get error?

What to do?

I have tried using X = X.Reshape(11); but It fails... if I use X = X.Reshape(10); it just do not draw anything

Answer 1

surfaces plot meshes. one must provide a mesh in order to give the surface the chance to understand how to connect the points, which points are meant to be neighbors.

the reshape should not be a problem since the original data must represent the points for a mesh/matrix anyway. so the reshape to that matrix will certainly work.

reshape(10) creates a vector of length 10. since vectors do represent a line at most but not an area - nothing is drawn. remember: surfaces draw meshes or matrices.