[英]Convert a list of strings to a single string
List<string> MyList = (List<string>)Session["MyList"];
MyList
contains values like: 12
34
55
23
. MyList
包含如下值: 12
34
55
23
。
I tried using the code below, however the values disappear. 我尝试使用下面的代码,但值消失了。
string Something = Convert.ToString(MyList);
I also need each value to be separated with a comma (" ,
"). 我还需要用逗号(“
,
”)分隔每个值。
How can I convert List<string> Mylist
to string
? 如何将
List<string> Mylist
转换为string
?
string Something = string.Join(",", MyList);
Try this code: 试试这段代码:
var list = new List<string> {"12", "13", "14"};
var result = string.Join(",", list);
Console.WriteLine(result);
The result is: "12,13,14"
结果是:
"12,13,14"
Or, if you're concerned about performance, you could use a loop, 或者,如果您担心性能,可以使用循环,
var myList = new List<string> { "11", "22", "33" };
var myString = "";
var sb = new System.Text.StringBuilder();
foreach (string s in myList)
{
sb.Append(s).Append(",");
}
myString = sb.Remove(sb.Length - 1, 1).ToString(); // Removes last ","
This Benchmark shows that using the above loop is ~16% faster than String.Join()
(averaged over 3 runs). 该Benchmark显示使用上述循环比
String.Join()
快了约16%(平均超过3次运行)。
Entirely alternatively you can use LINQ, and do as following: 完全可以使用LINQ,并执行以下操作:
string finalString = collection.Aggregate("", (current, s) => current + (s + ","));
However, for pure readability, I suggest using either the loop version, or the string.Join mechanism. 但是,为了纯粹的可读性,我建议使用循环版本或string.Join机制。
You can make an extension method for this, so it will be also more readable: 您可以为此创建一个扩展方法,因此它也更具可读性:
public static class GenericListExtensions
{
public static string ToString<T>(this IList<T> list)
{
return string.Join(",", list);
}
}
And then you can: 然后你可以:
string Something = MyList.ToString<string>();
I had to add an extra bit over the accepted answer. 我不得不在接受的答案上多加一点。 Without it, Unity threw this error:
没有它,Unity抛出了这个错误:
cannot convert `System.Collections.Generic.List<string>' expression to type `string[]'
The solution was to use .ToArray()
解决方案是使用
.ToArray()
List<int> stringNums = new List<string>();
String.Join(",", stringNums.ToArray())
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