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OpenCL - 两次传递image2d_t以获取内核的读写权限？

[英]OpenCL - Pass image2d_t twice to get both read and write from kernel?

原文 2014-08-04 08:32:08 0 1 image/ kernel/ opencl

In my OpenCL kernel I would like to both read and write to an image2d_t object. 在我的OpenCL内核中，我想读写一个image2d_t对象。 According to OpenCL standard I can only specify either __read_only or __write_only. 根据OpenCL标准，我只能指定__read_only或__write_only。 However, I figured if I send the same cl_mem as two separate kernel arguments (one with __read_only and one with __write_only) I can do both. 但是，我想如果我发送相同的cl_mem作为两个单独的内核参数（一个用__read_only，一个用__write_only）我可以做两个。

Probably when I do a write followed by a read, I might get the old value(?) but in my case I would like the old value first, update it and write it back to the image. 可能当我写一个写入后读取时，我可能会得到旧的值（？）但在我的情况下我首先想要旧值，更新它并将其写回图像。 A simple example would be "increment each pixel by 1". 一个简单的例子是“将每个像素增加1”。 It looks like it works in 99.9% but gives me artifacts sometimes. 它看起来像99.9％，但有时给我文物。

Does anybody know if this is possible at all or if I have to expect undefined behaviour? 有人知道这是否可行或者我是否需要预期未定义的行为？

1 个解决方案

According to OpenCL standard, one Image can be used either for reading, or for writing within one kernel. 根据OpenCL标准，一个Image可用于读取或在一个内核中写入。 So, if you need to read-write into same memory object, you have to use 2 Images, or switch to regular Buffer. 因此，如果需要读写同一个内存对象，则必须使用2个图像，或切换到常规缓冲区。 No guarantee can be made that your kernel will work fine. 不能保证你的内核能正常工作。