Python将列表转换为具有键值的字典

Question

I am getting json response from SOLR via PySolr , everything works fine, just that Facet fields are coming in inconsistent format , below is the facet fields

LocalityId = [ "14008",1,"14293",4,]

Now I need to convert the above list into Key-Value pair (Dictionary), likewise

LocalityId = {"14008":"1", "14293":"4"}

How to achieve this with python ?

Edit : Yes I know its not standard list format , but I didnt created it , blame solr

Edit : Why -1 , stackoverflow has become a place for revenge and random outburst! tell me here folk where I am wrong ??

Answer 1

Using slicing and zip you can create a dict like so assuming your list is called l :

dict(zip(l[::2], l[1::2]))

l[::2] will get every 2nd element of the list starting at index 0, in the same manner l[1::2] get every 2nd element starting at index 1.

l = ["14008", 1, "14293", 4]
l[::2] # ['14008', '14293']
l[1::2] # [1, 4]

These two lists are then zip ped together to create the dict.

EDIT As suggested in the comments the keys should be strings as well so we can use map to transform them. The code will become:

dict(zip(l[::2], map(str, l[1::2])))

Answer 2

You can use zip and dict for convert to your list to expected dictionary :

>>> l=[ "14008",1,"14293",4,]
>>> dict(zip(l[::2],l[1::2]))
{'14008': 1, '14293': 4}

Answer 3

Another way is to use dict comprehension.

l = ["14008", 1, "14293", 4]
{l[i*2]: l[i*2+1] for i in range(int(len(l)/2))}