将python列表转换为仅具有键的字典，没有值

Question

I have a list of room names in python, however I need it to be a dictionary, simply in the form {"room1", "room2", "room3"}

Currently, my code can take the list and turn to a dictionary with both values and keys, ie {"room1":0, "room2":1, "room3": 2} etc.

my code is as follows:

rooms = ["G5a", "G5b", "G11"]
roomdict = dict(zip(rooms,range(len(rooms))))

print(roomdict)

But, this is not the format I need my dictionary to be in - thanks for your help in advanace :)

Answer 1

What you need is a set :

A set is an unordered collection of items. Every element is unique (no duplicates) and must be immutable (which cannot be changed).

rooms = ["G5a", "G5b", "G11"]
print(set(rooms))

OUTPUT:

{'G5b', 'G5a', 'G11'}

Answer 2

On the odd chance that your really need a dict with keys and empty values:

mydict = {"room1" : None, "room2": None, "room3" : None}

You could use the dict.fromkeys() method:

rooms = ["G5a", "G5b", "G11"]
roomdict = dict.fromkeys(rooms, None)

print(roomdict)

Output:

{'G5b': None, 'G11': None, 'G5a': None}