如何使用python从1d数组创建具有3个元素的2d数组

Question

signals=([1998  ,1968  ,1937  ,1827  ,2027,2286  ,2484  ,2266  ,2107  ,1690,1808  ,1927  ,1924  ,1959  ,1889,1819  ,1824  ,1979  ,1919  ,1845,1801  ,1799  ,1952  ,1956  ,1969,2044  ,2100  ,2103  ,2110  ,2375,
    2030  ,1744  ,1699  ,1591  ,1770,1950  ,2149  ,2200  ,2294  ,2146,2241  ,2369  ,2251  ,2126  ,2000,1759  ,1947  ,2135  ,2319  ,2352,2476  ,2296  ,2400  ,3126  ,2304,
    2190  ,2121  ,2032  ,2161  ,2289,2137  ,2130  ,2154  ,1831  ,1899,2117  ,2266  ,2176  ,2089  ,1817,2162  ,2267])

Vectors=[[signals[i-1],signals[i+1],signals[i+3]] for i in range(1,len(signals-4))]
print Vectors

TypeError                                 Traceback (most recent call last)
<ipython-input-2-6f5b7430197d> in <module>()
     16     2190  ,2121  ,2032  ,2161  ,2289,2137  ,2130  ,2154  ,1831  ,1899,2117  ,2266  ,2176  ,2089  ,1817,2162  ,2267])
     17 
---> 18 Vectors=[[signals[i-1],signals[i+1],signals[i+3]] for i in range(1,len(signals-4))]
     19 print Vectors
     20 

TypeError: unsupported operand type(s) for -: 'list' and 'int'


Expected Output:[[signals[0],signals[2], signals[4]],[signals[1],signals[3],signals[5]],[signals[2],signals[4],signals[6]]] 

Answer 1

您的括号未正确放置： len(signals-4)应该为len(signals) - 4 。

Answer 2

错误在您的range函数中，您需要对signals加上括号，因为您要从signals长度列表中减去4：

range(1,len(signals)-4))