how to create 2d array with 3 elements from 1d array using python

Question

signals=([1998  ,1968  ,1937  ,1827  ,2027,2286  ,2484  ,2266  ,2107  ,1690,1808  ,1927  ,1924  ,1959  ,1889,1819  ,1824  ,1979  ,1919  ,1845,1801  ,1799  ,1952  ,1956  ,1969,2044  ,2100  ,2103  ,2110  ,2375,
    2030  ,1744  ,1699  ,1591  ,1770,1950  ,2149  ,2200  ,2294  ,2146,2241  ,2369  ,2251  ,2126  ,2000,1759  ,1947  ,2135  ,2319  ,2352,2476  ,2296  ,2400  ,3126  ,2304,
    2190  ,2121  ,2032  ,2161  ,2289,2137  ,2130  ,2154  ,1831  ,1899,2117  ,2266  ,2176  ,2089  ,1817,2162  ,2267])

Vectors=[[signals[i-1],signals[i+1],signals[i+3]] for i in range(1,len(signals-4))]
print Vectors

TypeError                                 Traceback (most recent call last)
<ipython-input-2-6f5b7430197d> in <module>()
     16     2190  ,2121  ,2032  ,2161  ,2289,2137  ,2130  ,2154  ,1831  ,1899,2117  ,2266  ,2176  ,2089  ,1817,2162  ,2267])
     17 
---> 18 Vectors=[[signals[i-1],signals[i+1],signals[i+3]] for i in range(1,len(signals-4))]
     19 print Vectors
     20 

TypeError: unsupported operand type(s) for -: 'list' and 'int'


Expected Output:[[signals[0],signals[2], signals[4]],[signals[1],signals[3],signals[5]],[signals[2],signals[4],signals[6]]] 

Answer 1

您的括号未正确放置： len(signals-4)应该为len(signals) - 4 。

Answer 2

错误在您的range函数中，您需要对signals加上括号，因为您要从signals长度列表中减去4：

range(1,len(signals)-4))