从任意原点找到两个向量之间的角度

Question

I would like to know how to get the angle on the picture when the origin is not O(0,0,0), but (a, b, c) where a, b, and c are variables.

B is a point that makes 90 degrees with A(d, e, f) and the origin.

The image is here:

Answer 1

First, subtract the origin from A and B:

A = A - origin
B = B - origin

Then, normalize the vectors:

A = A / ||A||
B = B / ||B||

Then find the dot product of A and B:

dot = A . B

Then find the inverse cosine. This is your angle:

angle = acos(dot)

(Note that the result is in radians. To convert to degrees, multiply by 180 and divide by π.)

Here is C++ source code that uses GLM to implement this method:

float angleBetween(
 glm::vec3 a,
 glm::vec3 b,
 glm::vec3 origin
){
 glm::vec3 da=glm::normalize(a-origin);
 glm::vec3 db=glm::normalize(b-origin);
 return glm::acos(glm::dot(da, db));
}

Answer 2

First, subtract the origin from A and B:

A = A - origin
B = B - origin

Then take the inverse cosine of their ratio of their magnitudes:

angle = acos(|B|/|A|)

Answer 3

then angle signed :

 double degrees(double radians)
{
    return (radians*180.0)/M_PI;
}

 double angle=atan2(v1.x*v2.x+v1.y*v2.y,v1.x*v2.y-v1.y*v2.x);
             angle=degrees(angle);