比较具有相同键的字典值

Question

Is there a clean, pythonic way to do the following?

1. compare all values from one dictionary to another without iterating over keys and comparing values?

I'm thinking either a list comprehension or a use of all() would play into this

right now I'm thinking that

for key in dict:
   if dict[key] > otherDict[key]
       return False
return True

any ideas?

Answer 1

给定两个字典dict1和dict2 ，可以将all()与生成器结合使用：

all(v <= dict2.get(k) for k, v in dict1.iteritems())

Answer 2

for key in dict:
   if dict[key] > otherDict[key]:
       return False
return True

is the same as

return not any(dict[key] > otherDict[key] for key in dict)

any() stops as soon as a true value is found which not then complements.

In a function context