如何在系统Verilog中使用fork块中的generate

Question

favorite In my testcase, I write one program like below"

define NUM_TEST 10
program test();
   bit [31:0] a[NUM_TEST]; 
   bit [31:0] b[`NUM_TEST]; 
   .... 
   initial begin 
     ..... 
     fork 
        aaa (a[0], b[0]); 
        aaa (a[1], b[1]); 
        ................ 
        aaa (a[9], b[9]); 
     join 
     ..... 
  end 
  task aaa (bit [31:0] a, bit [31:0] b); 
    ..... 
  endtask 
endmodule

As you see, I call task aaa with NUM_TEST time (I want all tasks excuted at the same time). Is there any way to reduce my code such as:

  **fork
      genvar k;
      generate
         (for k=0; k<NUM_TEST; k++) 
            aaa(a[k], b[k]); 
      endgenerate 
    join** 

(Of course, above code is wrong syntax);

FYI: I don't want to use like :

   fork 
      for (int i=0; i<`NUM_TEST; i++) 
        aaa(a[i], b[i]); 
   join 

-> this is wrong for my idea because task executed in order, not the same time.

Please help me :(

Answer 1

What you want is a combination of fork/join_none and wait fork

module test;
`define NUM_TEST 10
program test();
   bit [31:0] a[`NUM_TEST]; 
   bit [31:0] b[`NUM_TEST]; 
   .... 

 initial begin 
     ..... 
       for (int i=0; i<`NUM_TEST; i++) 
         fork
            automatic int j = i;        
            aaa(a[j], b[j]); 
         join_none
       wait fork;
     ....
   end