[英]Scala Breeze expansion matrix
In Octave/Matlab I can expand an identity matrix as follows. 在Octave / Matlab中,我可以如下扩展一个单位矩阵。
>> I = eye(3)
I =
Diagonal Matrix
1 0 0
0 1 0
0 0 1
>> A = [ 3 2 3 2 2 1 3 2 2 1 ]
>> E = I(:, A)
E =
0 0 0 0 0 1 0 0 0 1
0 1 0 1 1 0 0 1 1 0
1 0 1 0 0 0 1 0 0 0
How can I achieve the same thing (ie obtain E from A, possibly using I) with Scala/Breeze ? 如何使用Scala /微风实现同一件事(即从A获得E,可能使用I)?
Got it. 得到它了。 Actually very similar to Octave. 其实很像八度。
scala> val I = DenseMatrix.eye[Int](3)
I: breeze.linalg.DenseMatrix[Int] =
1 0 0
0 1 0
0 0 1
scala> val A = DenseMatrix(2, 1, 2, 1, 1, 0, 2, 1, 1, 0) // zero based in breeze
scala> I(::, A.toArray.toSeq)
res26: breeze.linalg.SliceMatrix[Int,Int,Int] =
0 0 0 0 0 1 0 0 0 1
0 1 0 1 1 0 0 1 1 0
1 0 1 0 0 0 1 0 0 0
The caveats are: 注意事项是:
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