轮廓和轮廓f的使用

Question

I have a list of points:

pointList = [ [x1,y1,z1], [x2,y2,z2], ... [xn,yn,zn]]

and I want to draw a contour plot of this set of points.

I try:

import matplotlib.pyplot as plt
pointList = [ [x1,y1,z1], [x2,y2,z2], ... [xn,yn,zn]]
x = [el[0] for el in pointList]
y = [el[1] for el in pointList]
z = [el[2] for el in pointList]
plt.contourf(x,y,z)
plt.show()

but I have this exception:

TypeError: Input z must be a 2D array.

This is strange because in the documentation of matplotlib I find:

Call signatures:
contour(Z)
make a contour plot of an array Z. The level values are chosen automatically.
contour(X,Y,Z)
X, Y specify the (x, y) coordinates of the surface

So I don't understand why it fails ...

Answer 1

In either case, contour(Z) , or contour(X,Y,Z) , the input Z must be a 2D array.

If your data does not live on a grid, you either need to interpolate it to a grid or you cannot use contour.

An easy alternative is to use tricontour .

import matplotlib.pyplot as plt
import numpy as np
pointList = [ [x1,y1,z1], [x2,y2,z2], ... [xn,yn,zn]]
pointList = np.array(pointList)
plt.tricontour(pointList[:,0],pointList[:,1],pointList[:,2])
plt.show()

There is a good example which compares tricontour with a contour of interpolated data: tricontour_vs_griddata .

You may also look at:

• Plotting Isolines/contours in matplotlib from (x, y, z) data set (which has an easy example for both, tricontour and interpolated contour)
• matplotlib contour/contourf of **concave** non-gridded data (for the case that your data is concave)