[英]Circle contour in space (threejs) (3D)
How to delete this line in this fugure http://joxi.ru/gmvl7YwT7Eg3Aa ? 如何在此fugure http://joxi.ru/gmvl7YwT7Eg3Aa中删除此行? I need only contour
我只需要轮廓
const intersection = (a, b, c, heightC) => {
return (u, v) => {
const height = heightC || c;
const size = 5;
u = u * height;
v = 2 * v * Math.PI;
const x = a * size * Math.sqrt(u) * Math.cos(v);
const y = c;
const z = b * size * Math.sqrt(u) * Math.sin(v);
return new Three.Vector3(x, y, z);
}
}
export const projectionIntersection = (a, b, heightC) => {
const geom = new Three.ParametricGeometry(intersection(a, b, 1, heightC), 1, 25);
const math = new Three.MeshPhongMaterial({ color: 0x00FF00, wireframe: true });
const mesh = new Three.Mesh(geom, math);
return mesh;
}
Who can help me? 谁能帮我?
parametric geometry as a mesh will create faces, which means creating linkages between the center and each point along the edge. 作为网格的参数化几何将创建面,这意味着在中心和沿边缘的每个点之间创建链接。 If you want just a line strip to draw a circle, take a look at Line Object .
如果只想用一条线画一个圆,请看一下Line Object 。 It looks like you can do what you're doing already, just pushing the Vector3 you create to the vertices of geometry and making a Line out of it.
看起来您可以完成已经做的事情,只需将创建的Vector3推到几何图形的顶点,然后在其中绘制一条直线即可。
Cheap and rough solution with a circle: 便宜又粗糙的解决方案:
var circleGeom = new THREE.CircleGeometry(1, 32);
circleGeom.vertices.shift();
circleGeom.vertices.push(circleGeom.vertices[0].clone());
var circle = new THREE.Line(circleGeom, new THREE.LineBasicMaterial({color: "yellow"}));
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