与常规缓冲区和制服相比，OpenGL纹理单元背后的原因是什么？

Question

I am very new to the OpenGL API and just discovered textures and how to use them. The generated texture buffers are not bound in the same way as regular uniforms are bound and instead use glActiveTexture , followed by a bind rather than just supplying the texture to the shaders via glUniform as we do with other constants.

What is the reasoning behind this convention?

The only reason I can think of is to utilize the graphics card's full potential and texture processing capabilities instead of just binding buffers directly. Is this correct reasoning, or is it simply the way the API was implemented?

No reasoning is given on the official wiki, just says that it's weird: "Binding textures for use in OpenGL is a little weird" https://www.khronos.org/opengl/wiki/Texture

Answer 1

Your question can be interpreted in two ways.

"Why do we bind textures to the context rather than to the shader?"

Because that would make it needlessly difficult to have multiple shaders use the same textures. Note that pretty much no graphics API directly attaches the texture to the program. Not D3D of any version, not Metal, nor even Vulkan.

Textures are resources used by shaders. But they are not part of the shader.

"Why do we treat textures differently from a general array of values?"

In modern OpenGL, shaders have access to several different kinds of resources: UBOs, SSBOs, textures, and images. Each of these kinds of resources ultimately represents a potentially distinct part of the graphics hardware.

A storage block is not just a uniform block that can be bigger. Storage buffers represent the shader doing global memory accesses, while uniform blocks are often copied directly into the shader execution units. In the latter case, accessing their data is much faster, but that also means that you're limited by how much storage those execution units can have.

Now, this is not true for all hardware (AMD's GCN hardware treats the two almost identically, which is why their UBO limits are so large ). But it is true of much hardware.

Textures are even more complicated, because implementations need to be able to store their data in an optimal way for performance reasons. As such, texture storage formats are opaque. They're even opaque in ostensibly low-level APIs like Vulkan. Oh sure, linear formats exist, but implementations aren't required to let you read from them at all.

So textures are not just constant arrays.

Answer 2

You are comparing two completely different things

A texture object can (somehow) be compared to a buffer object. The texture is bound by a combination of glActiveTexture and glBindTexture to a texture unit, whereas a buffer is bound by glBindBuffer which is kind-off similar.

A texture sampler uniform is a uniform in the shader and should thus be compared with other uniforms. This sampler is set by a glUniform1i call.