[英]How could I plot 3D grid using mplot3d and numpy array?
I am trying to plot a 3D NumPy Array which has integer values. 我正在尝试绘制具有整数值的3D NumPy数组。
import numpy as np
def build(self):
grid = np.empty((10,10,10))
grid = grid.astype(np.int)
grid.fill(-1)
return grid
The previous method builds a 3D grid and fills with -1 value. 先前的方法将构建3D网格并以-1值填充。 In this case, -1 is to representation of empty cell.
在这种情况下,-1表示空白单元格。
Putting 3 elements in this grid, for example, in the positions (0,0,0), (0,0,1) y (5,5,5) I do not see same number of elements after plot. 在网格中放置3个元素,例如,在(0,0,0),(0,0,1)y(5,5,5)的位置上,绘制后我看不到相同数量的元素。 I attach an image here
我在这里附上图片
.
。
There is a fourth element on the right of the image (with minor tonality). 图像的右边有第四个元素(具有较小的色调)。
My code to plot the grid is as given below: 我绘制网格的代码如下所示:
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
def plot_grid(self, np_grid):
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
x = np_grid.sum(0)
y = np_grid.sum(1)
z = np_grid.sum(2)
ax.scatter(x, y, -z, zdir='z', c='red')
plt.show()
I think I am not getting x,y,z
vectors correctly. 我认为我没有正确获得
x,y,z
向量。 How could I get x,y,z
from ndarray
correctly? 我怎样才能正确地从
ndarray
获得x,y,z
?
I believe your problem is that you need to pass the x, y, and z as arrays of their own: 我相信您的问题是您需要将x,y和z作为它们自己的数组传递:
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
ax.scatter((0,0,5),(0,0,5),(0,1,5),zdir='z', c='red')
This should give you a plot like this: 这应该给你这样的情节:
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