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Libgdx不会从舞台上移除演员

[英]Libgdx dont remove actors from Stage

i have problem with libgdx. 我有libgdx问题。 I'm working on program, that have input for boxes and then you can chose algorhytm to sort them into truck. 我正在研究程序,输入框,然后可以选择algorhytm将其分类为卡车。

在此处输入图片说明

I have problem with removig boxes. 我在removig box上遇到问题。 After i use this code, which should remove all actors, which are Textures(boxes). 使用此代码后,应删除所有actor,即Textures(boxes)。

for(Actor actor : stage.getActors()){
        if(actor.getClass() == Textures.class){
            actor.remove();
        }
    }

Sorting algorithm work good and all boxes are in the truck, but it doesn't remove some of the old boxes. 排序算法运行良好,所有箱子都在卡车上,但它不会删除一些旧箱子。 在此处输入图片说明

Then i try to use delete them by actor.getName() . 然后我尝试使用actor.getName()删除它们。 Same result. 结果相同。 There is also code whitch create actors: 还有一些代码创建者:

for(Actor actor : stage.getActors()){
        if(actor.getName()!=null){
            if(actor.getName().equals("shape")){
                actor.remove();
            }
        }
    }

    //create actors
    for (ShapeMeasurments sh:shapes) {
        Textures textures = new Textures((sh.getX()*1.45f+30),sh.getY()*1.45f,sh.getWidth()*1.45f,
                sh.getHeight()*1.45f,sh.getMaterial());
        textures.setName("shape");
        stage.addActor(textures);
    }

I found a problem. 我发现了一个问题。 actor.remove() is problem in foreach loop. actor.remove()是foreach循环中的问题。 Removing actors in foreach loop can cause problems. 在foreach循环中删除参与者可能会导致问题。 So then i use actor.addAction(Actions.removeActor()); 所以然后我使用actor.addAction(Actions.removeActor()); and it works. 而且有效。 That was said in second answer 那是第二答案

And don't use if(actor.getClass() == Textures.class) comparing classes is not trivial operation, you should use actor.setName() and actor.getName() . 并且不要使用if(actor.getClass() == Textures.class)比较类并非无关紧要的操作,您应该使用actor.setName()actor.getName()

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