在scipy（python）中执行B样条拟合时，如何更改基本函数的数量？

Question

I have a discrete set of points (x_n, y_n) that I would like to approximate/represent as a linear combination of B-spline basis functions. I need to be able to manually change the number of B-spline basis functions used by the method, and I am trying to implement this in python using scipy. To be specific, below is a bit of code that I am using:

import scipy
spl = scipy.interpolate.splrep(x, y)

However, unless I have misunderstood or missed something in the documentation, it seems I cannot change the number of B-spline basis functions that scipy uses. That seems to be set by the size of x and y. So, my specific questions are:

1. Can I change the number of B-spline basis functions used by scipy in the "splrep" function that I used above?

2. Once I have performed the transformation shown in the code above, how can I access the coefficients of the linear combination? Am I correct in thinking that these coefficients are stored in the vector spl[1]?

3. Is there a better method/toolbox that I should be using?

Thanks in advance for any help/guidance you can provide.

Answer 1

Yes, spl[1] are the coefficients, and spl[0] contains the knot vector.

However, if you want to have a better control, you can manipulate the BSpline objects and construct them with make_interp_spline or make_lsq_spline, which accepts the knot vector and that determines the b-spline basis functions to use.

Answer 2

You can change the number of B-spline basis functions, by supplying a knot vector with the t parameter. Since there is a connection number of knots = number of coefficients + degree + 1 , the number of knots will also define the number of coefficients (== the number of basis functions).

The usage of the t parameter is not so intuitive since the given knots should be only the inner knots. So, for example, if you want 7 coefficients for a cubic spline you need to give 3 inner knots. Inside the function it pads the first and last (degree+1) knots with the xb and xe (clamped end conditions see for example here ). Furthermore, as the documentation says, the knots should satisfy the Schoenberg-Whitney conditions.

Here is an example code that does this:

# Input:
x = np.linspace(0,2*np.pi, 9)
y = np.sin(x)

# Your code:
spl = scipy.interpolate.splrep(x, y)
t,c,k = spl  # knots, coefficients, degree (==3 for cubic)

# Computing the inner knots and using them:
t3 = np.linspace(x[0],x[-1],5)  # five equally spaced knots in the interval
t3 = t3[1:-1]  # take only the three inner values

spl3 = scipy.interpolate.splrep(x, y, t=t3)

Regarding your second question, you're right that the coefficients are indeed stored in spl[1] . However, note that (as the documentation says) the last (degree+1) values are zero-padded and should be ignored.

In order to evaluate the resulting B-spline you can use the function splev or the class BSpline . Below is some example code that evaluates and draws the above splines (resulting in the following figure):

xx = np.linspace(x[0], x[-1], 101)  # sample points
yy = scipy.interpolate.splev(xx, spl) # evaluate original spline
yy3 = scipy.interpolate.splev(xx, spl3)  # evaluate new spline

plot(x,y,'b.')  # plot original interpolation points
plot(xx,yy,'r-', label='spl')
plot(xx,yy3,'g-', label='spl3')