[英]Generating a function in R incorporating a pdf
How would I generate function y=2+3*xi+ei where ei=iidN(0,3^2) in R?我将如何在 R 中生成函数 y=2+3*xi+ei 其中 ei=iidN(0,3^2) ? I then want to plot and apply a linear regression model against it using x, which is just a simple sequence of data
然后我想使用 x 绘制并应用线性回归模型,这只是一个简单的数据序列
Define function定义函数
f <- function(x, a=2, b=3) a + b * x + rnorm(length(x), mean=0, sd=3^2)
Generate some points产生一些点
set.seed(123)
data <- data.frame(x=0:10, y=f(0:10))
Fit linear model拟合线性模型
fit <- lm(y~x, data=data)
summary(fit)
#Call:
#lm(formula = y~x, data=data)
#
#Residuals:
# Min 1Q Median 3Q Max
#-12.832 -6.181 -1.144 6.220 13.823
#
#Coefficients:
# Estimate Std. Error t value Pr(>|t|)
#(Intercept) 4.027 5.183 0.777 0.4570
#x 2.917 0.876 3.330 0.0088 **
#---
#Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
#
#Residual standard error: 9.188 on 9 degrees of freedom
#Multiple R-squared: 0.552, Adjusted R-squared: 0.5022
#F-statistic: 11.09 on 1 and 9 DF, p-value: 0.008802
We see large uncertainty in (Intercept)
due to large error term.由于大的误差项,我们看到
(Intercept)
很大的不确定性。
Show data and fit显示数据和拟合
ggplot(data, aes(x=x, y=y)) +
geom_point() +
geom_smooth(method='lm', formula=y~x)
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