Uniform_int_distribution &lt;&gt;和 <int> ？

Question

I am a beginer for C++. I would like to ask that:

is std::uniform_int_distribution<> dis(1, 6); equal to std::uniform_int_distribution<int> dis(1,6); ?

Many thanks.

Answer 1

Yes.

From cppreference , std::uniform_int_distribution has default template argument. It defaults to int . Therefore, the following uses are equivalent:

std::uniform_int_distribution<> dis(1, 6);
std::uniform_int_distribution<int> dis(1, 6);

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The exact definition of this class looks like tihs:

template< class IntType = int >
class uniform_int_distribution;

IntType should be one of short , int , long , long long , unsigned short , unsigned int , unsigned long , or unsigned long long