[英]Flink DataSet.map get 'error: missing parameter type'
I am just start to learn Scala and Flink.我刚刚开始学习 Scala 和 Flink。 When I try to run demo codes as follow:
当我尝试按如下方式运行演示代码时:
private def demoFunction[T <: Vector](dataSet: DataSet[T])
: DataSet[(linalg.Vector[Double], linalg.Vector[Double])] = {
val metrics = dataSet.map{
v => (1.0, v.asBreeze, linalg.Vector.zeros[Double](v.size))
}.reduce{
// reduce code..
}
// ...
}
I got err info:我得到了错误信息:
Error: missing parameter type v => (1.0, v.asBreeze, linalg.Vector.zeros[Double](v.size))
The dependencies are follow:依赖关系如下:
If you have any ideas, please help.如果您有任何想法,请帮助。 Thanks in advance.
提前致谢。
Update on December 12. 12 月 12 日更新。
I fix this problem after adding a :T after v , It seems to clarify which type v is.我在v之后添加了一个:T后解决了这个问题,它似乎阐明了v是哪种类型。 But I am still confused with it.
但我仍然对此感到困惑。
val metrics = dataSet.map{
v:T => (1.0, v.asBreeze, linalg.Vector.zeros[Double](v.size))
}// ...
If Vector
in T <: Vector
is the same as linalg.Vector
then it takes a type parameter如果
Vector
in T <: Vector
与linalg.Vector
相同,则它需要一个类型参数
trait Vector[@spec(Int, Double, Float) V] extends VectorLike[V, Vector[V]] {
...
so it can't be just T <: Vector
, it should be T <: Vector[...something...]
.所以它不能只是
T <: Vector
,它应该是T <: Vector[...something...]
。
If Vector
in T <: Vector
is different from linalg.Vector
, then maybe you import breeze.linalg._
and Vector
is resolved as linalg.Vector
.如果
Vector
in T <: Vector
与linalg.Vector
不同,那么也许你import breeze.linalg._
并且Vector
被解析为linalg.Vector
。 So use fully qualified name所以使用完全限定名称
private def demoFunction[T <: yourpackage.yoursubpackage.Vector] ...
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