[英]np.reshape 1d array to 2d array - choosing right dimensions
I'm trying to reshape a 1d array to a 2d array with numpy's reshape:我正在尝试使用 numpy 的重塑将一维数组重塑为二维数组:
import numpy as np
inputArray =np.random.randint(low=0, high=4, size=160000)
inputArray_ = inputArray.reshape(-1,4000, 4000,4)
Which returns a value error:返回值错误:
ValueError: cannot reshape array of size 160000 into shape (400,400,4)
Use用
inputArray_ = np.reshape(inputArray, (-1, 2))
Or或者
inputArray_ = np.reshape(inputArray, (len(inputArray)/2,2))
since 400*400*4 = 640,000 is bigger than 160000 you cannot reshape.由于 400*400*4 = 640,000 大于 160000,因此您无法重塑。
You don't have enough values to fill the new shape.您没有足够的值来填充新形状。
640,000-160,000 = 480,000. 640,000-160,000 = 480,000。 you lack 480,000 values.你缺少 480,000 个值。
divide your shape of 160000 by the other dimensions-multiplicated, if a int is the result, it works.将您的 160000 形状除以其他维度 - 乘以,如果结果为 int,则它有效。
eg例如
inputArray_ = inputArray.reshape(-1,40, 40, 10)
this will result in a shape of [10,40,40,10]这将导致 [10,40,40,10] 的形状
since 160000 / (40*40*10) = 10 ---> 10 is the dim that the "-1" takes因为 160000 / (40*40*10) = 10 ---> 10 是“-1”所采用的暗淡
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