[英]Apply the same function on each record of a column in Pandas dataframe
I have a dataset with a date-time column with a specific format.我有一个具有特定格式的日期时间列的数据集。 I need to create new features out of this column that means I need to add new columns to the dataframe by extracting information from the above-mentioned date-time column.
我需要在此列中创建新功能,这意味着我需要通过从上述日期时间列中提取信息来将新列添加到 dataframe。 My sample input dataframe column is like below.
我的示例输入 dataframe 列如下所示。
id datetime feature2
1 12/3/2020 0:56 1
2 11/25/2020 13:26 0
The expected output is:预期的 output 为:
id date hour mints feature2
1 12/3/2020 0 56 1
2 11/25/2020 13 26 0
Pandas apply() method may not work for this as new columns are added. Pandas apply() 方法可能不适用于此,因为添加了新列。 What is the best way to do this?
做这个的最好方式是什么?
Is there any way which I can apply a single function on each record of the column to do this by applying on the whole column?有什么方法可以在列的每条记录上应用单个 function 来通过在整个列上应用来做到这一点?
.dt
accessor .dt
存取器import pandas as pd
df = pd.DataFrame({'id': [1, 2],
'datetime': ['12/3/2020 0:56', '11/25/2020 13:26'],
'feature2': [1, 0]})
df['datetime'] = pd.to_datetime(df['datetime'])
id datetime feature2
1 2020-12-03 00:56:00 1
2 2020-11-25 13:26:00 0
# create columns
df['hour'] = df['datetime'].dt.hour
df['min'] = df['datetime'].dt.minute
df['date'] = df['datetime'].dt.date
# final
id datetime feature2 hour min date
1 2020-12-03 00:56:00 1 0 56 2020-12-03
2 2020-11-25 13:26:00 0 13 26 2020-11-25
IICU重症监护病房
df.date=pd.to_datetime(df.date)
df.set_index(df.date, inplace=True)
df['hour']=df.index.hour
df['mints']=df.index.minute
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.