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与 Java AWT 的矩形交叉点

[英]Rectangle intersections with Java AWT

原文 2020-06-19 15:15:43 0 1 java/ awt/ java-2d

I have two rectangles, and I want to figure out which side they are intersecting on.我有两个矩形，我想弄清楚它们在哪一侧相交。 I can use Rectangle.intersects(Rectangle) but it only tells me that the rectangles are intersecting.我可以使用Rectangle.intersects(Rectangle)但它只告诉我矩形是相交的。 What I am trying to do is check whether the rectangle is intersecting on the x or y axis, but I am not sure how to do this.我想做的是检查矩形是否在 x 轴或 y 轴上相交，但我不确定该怎么做。

1 个解决方案

I am suggesting just using some basic math to determine where the rectangles are intersecting.我建议只使用一些基本数学来确定矩形相交的位置。

A rectangle has a location (upper left corner) and a width and a height.矩形具有位置（左上角）以及宽度和高度。

Say R1 is at (10,20) and R2 is at (40,50) .说R1在(10,20)和R2在(40,50) 。 Since R1 is to the left and above R2 , then that means that if R2 is intersecting R1 , R2 must be intersecting on the right and/or below R1 .由于R1在R2的左侧和上方，这意味着如果R2与R1相交，则R2必须在R1的右侧和/或下方相交。
But if R2 is not as wide as R1 , it may be intersecting only on the bottom of R1 .但如果R2 2 不如R1宽，则它可能仅在R1的底部相交。
Or if R2 is not as high as R1 , it may be intersecting only on the right of R1 .或者，如果R2不如R1高，则它可能仅在R1的右侧相交。
There is also the possibility that R1 and R2 are completely overlapping each other.也有可能R1和R2完全重叠。

So you will need to use the combination of the rectangles' locations and their sizes to determine exactly where the rectangles are intersecting.因此，您需要结合使用矩形的位置及其大小来确定矩形相交的确切位置。

The best thing to do is try and work this out on paper.最好的办法是尝试在纸上解决这个问题。 Then write your code and if you have any problems, post it and someone will assist.然后编写您的代码，如果您有任何问题，请发布它，有人会提供帮助。 When posting your answer, just edit your original post with the changes.发布您的答案时，只需使用更改来编辑您的原始帖子。