Java矩形交叉点

Question

java会计算矩形，其中一个在其他内部作为交叉，并返回一个交叉点，当我调用交集（Rectangle）时，它是一个较小的矩形？

Answer 1

Returns : the largest Rectangle contained in both the specified Rectangle and in this Rectangle

As far as I understand you case, the result would be the smaller Rectangle that is contained in the larger one.

Answer 2

scala> import java.awt.Rectangle
import java.awt.Rectangle

scala> val big = new Rectangle(0, 0, 10, 10)
big: java.awt.Rectangle = java.awt.Rectangle[x=0,y=0,width=10,height=10]

scala> val small = new Rectangle(2, 2, 3, 3)
small: java.awt.Rectangle = java.awt.Rectangle[x=2,y=2,width=3,height=3]

scala> big.intersection(small)
res0: java.awt.Rectangle = java.awt.Rectangle[x=2,y=2,width=3,height=3]

scala> small.intersection(big)
res1: java.awt.Rectangle = java.awt.Rectangle[x=2,y=2,width=3,height=3]