检查行值是否与列表中的值之一匹配，然后在新列中分配 1/0

Question

How can I create a new column in a pandas dataframe by following these conditions?

if column ' Ex ' match with one of the elements in this list l=['cnn', 'nba', 'agi', 'apple'] then:

Create a new column, S , having value 1 for those elements in the list above.

For example:

Original dataframe:

Ex

cnn
dog
mine
agi

Output expected:

Ex          S

cnn         1
dog         0
mine        0
agi         1

I would approach the problem as follows:

df['S']=df['Ex'].apply(lambda x: any([k in x for k in l]))

to check if a row matches (I do not want a 'contains' condition) one of the value within l . I do not know how to assign values 1 or 0, but I think adding an if statement.

Answer 1

You can just do isin

df['S']=df['Ex'].isin(l).astype(int)