[英]repeating a numpy array N times
hii experts i have a 1d numpy array and i want to repeat it 3 times vertically,嗨,专家,我有一个 1d numpy 数组,我想垂直重复 3 次,
my_input_array = [-1.02295637 -0.60583836 -0.42240581 -0.78376377 -0.85821456]
i tried the below code我试过下面的代码
import numpy as np
x=np.loadtxt(my_input_array)
x.concatenate()
however i get error...in this way...hope i will get some solution.Thanks.但是我得到错误...以这种方式...希望我能得到一些解决方案。谢谢。
my expected output should be as below我的预期输出应该如下
-1.02295637
-0.60583836
-0.42240581
-0.78376377
-0.85821456
-1.02295637
-0.60583836
-0.42240581
-0.78376377
-0.85821456
-1.02295637
-0.60583836
-0.42240581
-0.78376377
-0.85821456
Just use tile
method which multiplies the array with given shape and reshape
method to structure it.只需使用
tile
方法将数组与给定的形状相乘,并使用reshape
方法来构造它。 Use x.shape[0]*x.shape[1]
to change it into a column vector without explicitly giving the shape dimensions!使用
x.shape[0]*x.shape[1]
将其更改为列向量,而无需明确给出形状尺寸!
x=np.tile(x,(3,1))
y=x.reshape(x.shape[0]*x.shape[1])
np.tile(my_input_array, 3)
Output输出
array([-1.02295637, -0.60583836, -0.42240581, -0.78376377, -0.85821456,
-1.02295637, -0.60583836, -0.42240581, -0.78376377, -0.85821456,
-1.02295637, -0.60583836, -0.42240581, -0.78376377, -0.85821456])
Edit: just noticed @hpaulj's answer.编辑:刚刚注意到@hpaulj 的回答。 I'll still leave my answer but he mentioned np.tile first.
我仍然会留下我的答案,但他首先提到了 np.tile。
This is what you want:这就是你想要的:
x=np.concatenate([my_input_array, my_input_array, my_input_array])
for i in x:
print(i)
Output:输出:
-1.02295637
-0.60583836
-0.42240581
-0.78376377
-0.85821456
-1.02295637
-0.60583836
-0.42240581
-0.78376377
-0.85821456
-1.02295637
-0.60583836
-0.42240581
-0.78376377
-0.85821456
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