从一列中获取所有不同的值，其中另一列对于初始列中的每个值至少有两个不同的值

Question

I'm having a very large dataset (20GB+) and I need to select all distinct values from column A where there are at least two other distinct values in column B for each distinct value on column A.

For the following dataframe:

| A | B |
|---|---|
| x | 1 |
| x | 2 |
| y | 1 |
| y | 1 |

Should return only x because it has two distinct values on column B, while y has only 1 distinct value.

The following code does the trick, but it takes a very long time (as in hours) since the dataset is very large:

def get_values(list_of_distinct_values, dataframe):
    valid_values = []
    for value in list_of_distinct_values:
        value_df = dataframe.loc[dataframe['A'] == value]
        if len(value_df.groupby('B')) > 1:
            valid_values.append(value)
    return valid_values

Can anybody suggest a faster way of doing this?

Answer 1

I think you can solve your problem with the method drop_duplicates() of the dataframe. You need to use the parameters subset and keep (to remove all the lines with duplicates) :

import pandas as pd
df = pd.DataFrame({
    'A': ["x", "x", "y", "y"],
    'B': [1, 2, 1, 1],
})
df.drop_duplicates(subset=['A', 'B'], keep=False).drop_duplicates(subset=['A'])['A']