Spark：没有找到 java.util.UUID 的编码器

Question

I have a case class that contains a type field UUID. I use anorm to parse a Postgres table and I want to transform the list to a Dataset.

When I create the Dataset, I have this error No Encoder found for java.util.UUID

def encoder[T: Encoder] = implicitly[Encoder[T]]

val parser = Macro.namedParser[Vehicle]

val result = SQL(s"SELECT * FROM $tableName").as(parser.*)

spark.createDataset(result)(encoder[Vehicle])

How can I manage this error?

Thanks for your help.

Answer 1

There are no encoder for UUID in spark 2. you should use String instead.