[英]How to add text of count above mean and confidence interval errorbar python?
I have created an errorbar plot in matplotlib with the mean and confidence intervals of each bin.我在 matplotlib 中创建了一个误差条 plot,其中包含每个 bin 的平均值和置信区间。 Now, I am trying to add a text label above each errorbar that states the number of observations in each bin.
现在,我正在尝试在每个错误栏上方添加一个文本 label,说明每个 bin 中的观察数。 So far I have:
到目前为止,我有:
binned bin_count val_mean val_ci
(0.1, 0.3] 10 3.13 14.20
(0.3, 0.6] 40 -.1 12.98
(0.6, 0.9] 31 1.8 12.59
(0.9, 1.2] 4 .42. 1.42
bar1 = plt.errorbar(x = df.binned, y = df.val_mean,
yerr = df.val_ci, marker = 'o', linestyle = '', capsize = 4)
i = 0
for line in bar1.lines:
plt.text(x = line.get_xdata(), y = line.get_ydata()+ .1, s = str(df['bin_count'][i]))
i += 1
plt.show()
But I keep getting the errors:但我不断收到错误:
AttributeError: 'tuple' object has no attribute 'get_xdata'
and和
TypeError: only size-1 arrays can be converted to Python scalars
I have been looking at documentation on how to access the x and y values of Line2D object and what I have says get_xdata().我一直在查看有关如何访问 Line2D object 的 x 和 y 值以及我所说的 get_xdata() 的文档。
Also when testing out what happens when printing get_xdata() it outputs the bins like so:此外,在测试打印 get_xdata() 时会发生什么时,它会像这样输出 bin:
for line in bar1.lines:
print(line.get_xdata())
Output: Output:
['(.1, .3]', '(0.3, 0.6]', '(0.6, 0.9]', '(0.9, 1.2]']
AttributeError: 'tuple' object has no attribute 'get_xdata'
I'm not sure what to do to correctly access the coordinates of each bar and print the bin_count text on top of the error bars.我不确定如何正确访问每个条的坐标并在误差条顶部打印 bin_count 文本。 Any help greatly appreciated.
非常感谢任何帮助。
Update: Adding dataframe (df) code更新:添加 dataframe (df) 代码
df = pd.DataFrame({'binned': ['(0.1, 0.3]', '(0.3, 0.6]', '(0.6, 0.9]', '(0.9, 1.2]'],
'bin_count': [10, 40, 31, 4],
'val_mean': [3.13, -.1, 1.8, .42],
'val_ci': [14.20, 12.98, 12.59, 1.42]})
Is this something you are trying to achieve?这是你想要达到的目标吗?
import matplotlib.pyplot as plt
import numpy
df = numpy.array([[
0.1, 0.3, 10, 3.13, 14.2], [
0.3, 0.6, 40, -0.1, 12.98], [
0.6, 0.9, 31, 1.8, 12.59], [
0.9, 1.2, 4, 0.42, 1.42]])
bar1 = plt.errorbar(df[:, 0], y=df[:, 3], yerr=df[:, 4], marker='o', linestyle='', capsize=4)
xx = bar1.lines[0].get_xdata()
yy = bar1.lines[0].get_ydata()
for i in range(len(xx)):
plt.text(x=xx[i], y=yy[i] + .1, s=str(df[:, 2][i]))
i += 1
plt.show()
You can make the necessary changes on your df and it should still work in my opinion.您可以对您的 df 进行必要的更改,我认为它应该仍然有效。 The end result I achieved with this is shown here.
我用这个实现的最终结果显示在这里。
Now note that, in your case I assume your first column as an interval, but you can notice in your print statement that your interval is a string.现在请注意,在您的情况下,我假设您的第一列是一个间隔,但您可以在打印语句中注意到您的间隔是一个字符串。 I haven't invested any time in solving your interval problem as this question is intended for having bin counts as text.
我没有投入任何时间来解决您的间隔问题,因为这个问题旨在将 bin 计数为文本。
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