[英]Sort 3D array using sort indices of a 2D array
I have 2D and a 3D numpy array.我有 2D 和 3D numpy 阵列。 The 2d array A
has shape (N, 3)
and the 3d array B
has shape (N, 3, 3)
.二维阵列A
具有形状(N, 3)
,3d 阵列B
具有形状(N, 3, 3)
。 I want to sort A
along axis=1
and then apply that same sorting to array B
sorting along axis=2
.我想A
沿axis=1
排序,然后将相同的排序应用于数组B
沿axis=2
排序。
I know I can do我知道我能做到
sort_idxs = np.argsort(A, axis=1)
but then I don't know how to apply sort_idxs
in the way I need to array B
.但后来我不知道如何以我需要排列B
的方式应用sort_idxs
。 sort_idxs
has a shape of (N, 3)
like A
. sort_idxs
的形状为(N, 3)
如A
。 Somehow I need to map the first dimension of sort_idxs
to the first dimension of B
, map the second dimension of sort_idxs
to the 3rd dimension of B
, and ignore the second dimension of B
.不知何故,我需要将 sort_idxs 的第一维sort_idxs
到B
的第一维, map 将sort_idxs
的第二维到B
的第三维,并忽略B
的第二维。 How can I do this?我怎样才能做到这一点?
This can be solved using这可以使用解决
sort_idxs = np.argsort(A, axis=1)
B_sorted = np.take_along_axis(B, sort_idxs[:, np.newaxis, :], axis=2)
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