读取没有列名的 csv 文件 python

Question

Hi I wanted to ask that i got a data of 80 columns and all of them have no names and its 80 columns and 12500 rows long and there are blank columns between them

8,1,,0,1993,146,,2,1,,,,,,,,,,2.1,0.65,0.15,0.65,19.1,,18.03,,,19.6,,,0.06,,,,,,19.1,19.6294717,19.36473585,0.06,,,,51.25,19.3,23.3,-0.04,-0.04,0.34,0.07,0.16,,,0.16,,,,,,,,,,,,,,,,,,15.3,7.8,11.55,58,100,79,15.4,8,11.7

I want to use this csv file and i want to delete the extra blank columns which i might do from using the code line

data = data.dropna()

bur it only can delete the rows i think further more how can I access or name the particular column data = pd.read_csv('CollectedData.csv')

Answer 1

IIUC, use this pandas.read_csv with header=None and pandas.DataFrame.dropna on axis=1 :

data = pd.read_csv("CollectedData.csv", header=None).dropna(axis=1, how="all")

If you need to give names to each column, use names parameter:

cols_names= ["ColA", "ColB", "ColC", ..]

data = (
        pd.read_csv("CollectedData.csv",
                    header=None,
                    names=cols_names)
            .dropna(axis=1, how="all")
        )