[英]concat a varying value to a variable in python
instead of repeating the line multiple times can I concat a varying value in a variable so I change the variable after every iteration in a loop我可以在变量中连接一个不同的值,而不是多次重复该行,这样我就可以在循环中的每次迭代后更改变量
ac2=AgglomerativeClustering(n_clusters = 2, affinity = 'euclidean', linkage = 'average')
ac3=AgglomerativeClustering(n_clusters = 3, affinity = 'euclidean', linkage = 'average')
ac4=AgglomerativeClustering(n_clusters = 4, affinity = 'euclidean', linkage = 'average')
ac5=AgglomerativeClustering(n_clusters = 5, affinity = 'euclidean', linkage = 'average')
ac6=AgglomerativeClustering(n_clusters = 6, affinity = 'euclidean', linkage = 'average')
is there a method using for loop to make this shorter something like this-有没有一种方法使用 for 循环来缩短它,就像这样-
for i in range(2,7):
ac+i=AgglomerativeClustering(n_clusters = i, affinity = 'euclidean', linkage = 'average')
you can use a dictionary你可以用字典
val = {}
for i in range(2,7):
val["ac{0}".format(i)] = AgglomerativeClustering(n_clusters = i, affinity = 'euclidean', linkage = 'average')
print(val)
I would NOT RECOMMEND using the method below, but only for experimental purposes.我不会推荐使用下面的方法,但仅用于实验目的。
globals()
returns dict
of key
as variabls and the value
as the value assigned to the variable. globals()
返回key
的dict
作为变量, value
作为分配给变量的值。
for i in range(2, 7):
globals()[f'ac{i}'] = AgglomerativeClustering(n_clusters = i, affinity = 'euclidean', linkage = 'average')
It will create variables from ac2
to ac6
.它将创建从ac2
到ac6
的变量。
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