Toggle a button to be viewed after a checkbox has been checked, and disappear if unchecked

Question

Below I have code for a specific application that I am building with PHP. My job is User interface, and I have looked and looked for code on how to make this work.

With this form, it's using the latest update of Jquery UI to styalize the buttons and checkboxes. I need for the button to appear when a check box has been checked, and disappear when unchecked.

Haven't been able to find any code that works for this, and is driving me half insane, and lagging me behind.

<form name="purpose" method="post" action="" >
    <div id="radiosetPURPOSE">
        <input type="checkbox" id="radio1" name="homework" value="homework" ><label for="radio1" style="font-size: 13pt; width: 130px; height: 40px;">Homework</label>
        <input type="checkbox" id="radio2" name="computer" value="computer" ><label for="radio2" style="font-size: 13pt; width: 130px; height: 40px;">Computer</label>
    </div>
    <br />
    <div id="radiosetPURPOSE2">
        <input type="checkbox" id="radio3" name="books" value="books" ><label for="radio3" style="font-size: 13pt; width: 130px; height: 40px;">Books</label>
        <input type="checkbox" id="radio4" name="reading" value="reading" ><label for="radio4" style="font-size: 13pt; width: 130px; height: 40px;">Reading</label>                     
    </div>
    <br />
        <div id="radiosetPURPOSE3">
        <input type="checkbox" id="radio5" name="tutoring" value="tutoring" ><label for="radio5" style="font-size: 13pt; width: 130px; height: 40px;">Tutoring</label>                     
    </div>
    <br  /><br  /><br  /><br  />
        <div id="btnCheckin" style="display:none">   
        <button id="btnCheckinBtn" style="font-size: 18pt; width: 175px; height: 75px;">Check In</button>
    </div>
</form>

Answer 1

Seems I misread your question, and you want the button enabled when any checkbox is checked .

This will look and see if any checkboxes are ticked, within the form with name purpose .

$("input:checkbox").change(function() {    
  $("#btnCheckin").toggle(!!$('form[name="purpose"] > input:checkbox:checked').length))
});

Answer 2

IF I read your requirements properly, you need to check if ANY of the checkboxes are check to show the button, and if ALL are unchecked, hide it?

This can occur on a click or on a keyboard action so you need to check the change event for that. Wrap this up in a document ready handler, include jQuery and you are set.

$('input:checkbox').change(function () {
    if ($('input[type=checkbox]:checked').length > 0) {
        $('#btnCheckin').show();
    } else {
        $('#btnCheckin').hide();
    }
});

Here is a fiddle with your markup: http://jsfiddle.net/GGdtw/

Answer 3

When you click the checkbox, check to see if it is checked or unchecked, and based on that, enable or disable the button. (Using jQuery)

<script>
    $(document).ready(function() {

        $("#checkbox").click(function() {
            if (("#checkbox").is(":checked")) {
                //button show (.show())
            else {
                //disable the button (.hide())
            }
        });
    });
</script>

Also, get rid of the "display: none;" in the button style.

Fiddle: http://jsfiddle.net/mbYby/

Answer 4

You can also use jQuery '.toggle()':

http://api.jquery.com/toggle/