Getting the data for each month

Question

So what I want to do is basically this:

Month and Year:

-All the data sent on that month and year

For example: February 2013:

-The posts on this date

March 2013:

-The posts on this date

and so on.

I have a date column on my table and it has the following format: day.month.year

I am using PHP and MySQL.

I have my own MVC framework that I'm using. I will simplify it to make it more understanble here. The function to fetch data:

function selectAll($sql){

    $find = $this->prepare($sql);     
    $find->execute();                      
    $fetchdata = $find->fetchAll(PDO::FETCH_ASSOC);        
    return $fetchdata;
}

And the code to get the dates :

    $sql = "Select YEAR(Date) AS year, MONTH(Date) AS month, Headline from blog";
$data =  $this->db->selectAll($sql);
foreach($data as $key => $value) { 
        $date[] = $value['month'].'.'.$value['year'];

        }
$dateunique = array_unique($date);

This give me the results for the dates but I cannot figure out how to put the correct data under each date.

Answer 1

Use DATE_FORMAT mysql function.

Example

SELECT DATE_FORMAT(date_field,'%M') as Month,DATE_FORMAT(date_field,'%Y') as Year FROM table_name

and then debug result of query you will see two extra column for month and year then display it as your desire.

if date_field is varchar then use str_to_date mysql function.

SELECT STR_TO_DATE(date_field,'%M') as Month, STR_TO_DATE(date_field,'%Y') as Year FROM table_name;

OP question update

Try GROUP_CONCAT

SELECT
*,
GROUP_CONCAT(created) AS month
FROM
table_name
GROUP BY MONTH(created) DESC;

Answer 2

1. Convert the varchar date field into exact date using str_to_date function
2. Using DATE_FORMAT you can select month wise record
3. Where $input is %Y-%m format // ex: 02-2013-> feb 2013

 SELECT * FROM `table` WHERE DATE_FORMAT(str_to_date(`date_column`, '%d/%m/%Y'), '%Y-%m')= '".$input."';