Bash shell program starts C programs

Question

Is there a way for a bash shell program, that takes a command-line argument x , that will make x (C program) processes start?

.

Answer 1

It's fairly simple:

#!/bin/bash
$1

If you want to pass the rest of the parameters as parameters to the function, do this:

$@

(ie foo.sh echo hi executes echo hi )

If you want to steal some parameters and pass others, use shift :

param1=$1
shift
echo $@ # contains parameters 2+

Answer 2

#!/bin/bash
(( $# != 1 )) && echo "Usage: $0 num" && exit -1
for (( c=1; c<=$1; c++ ))
do
   ./run_c_program &
done
wait

• $1 represents the first command line argument
• $# represents the number of arguments
• $0 is the name of the script
• run_c_program is the executable of the c program
• with & the c programs are executed in the background
• with wait the scripts waits for the c programs to terminate (optional)

Answer 3

您可以尝试使用system功能

system("./script.sh");