This are my tables
Message
Person
This is my Gridview source
<asp:TemplateField ShowHeader="False">
<ItemTemplate>
<asp:LinkButton ID="LinkButton1" runat="server" CausesValidation="False"
CommandName="Select" Text="Select"></asp:LinkButton>
<asp:LinkButton ID="LinkButton2" runat="server" CausesValidation="False"
CommandName="Delete" Text="Delete"></asp:LinkButton>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="RecipientID" SortExpression="Person.LastName">
<ItemTemplate>
<asp:Label ID="Label1" runat="server" Text='<%# Bind("Person.LastName") %>'></asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:BoundField DataField="Subject" HeaderText="Subject"
SortExpression="Subject" />
<asp:BoundField DataField="Message1" HeaderText="Message"
SortExpression="Message1" />
<asp:BoundField DataField="Status" HeaderText="Status"
SortExpression="Status" />
<asp:BoundField DataField="Date" HeaderText="Date" SortExpression="Date" />
<asp:TemplateField HeaderText="SenderID" SortExpression="Person.LastName">
<ItemTemplate>
<asp:Label ID="Label2" runat="server" Text='<%# Bind("Person.LastName") %>'></asp:Label>
</ItemTemplate>
</asp:TemplateField>
This is the result
Can you guys help me to display the Sender's name ? :) Thank you guys in advance! I'm using Entity Datasource
UPDATE
I'm logging in as User Carlo
Sender display the user that's logged in not the true sender in the Message Table
this is my Entity Model
You've already got the navigation properties you need for this, but their names conceal their role. You use Message.Person
to get the sender's name, likewise you can user Message.Person1
to get the recipient's name.
I would rename the properties Person
and Person1
into Sender
and Recipient
, respectively. Thus, they match the primitive foreign key names SenderID
and RecipientID
. Likewise, you could rename the Person.Messages
properties into MessagesSent
and MessagesReceived
.
In the template you can use Sender.LastName
and Recipient.LastName
.
使用此查询
select m.MessageID,m.ReceipientID,m.Subject,m.senderID,p.UserName,p.FirseName from Message m inner join Person p on m.SenderID= p.ID
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