Find two numbers in string with Ruby using Regex

Question

I have a string that looks like this:

Results 1 - 10 of 20

How would I find the number 10 and 20 of that sentence using regex in Ruby?

Something like:

first_number, second_number = compute_regex(my_string)...

Thanks

Answer 1

Like so:

first, second = *source.scan(/\d+/)[-2,2]

Explanation

\\d+ matches any number

scan finds all matches of its regular expression argument in source

[-2,2] returns the last two numbers in an array: starts at index -2 from end, returns next 2

* splat operator unpacks these two matches into the variables first and second ( NOTE : this operator is not necessary, you can remove this, and I like the concept )

Answer 2

Try this:

a = "Results 1 - 10 of 20"
first_number, second_number = a.match(/\w+ (\d) \- (\d+) of (\d+)/)[2..3].map(&:to_i)

The map piece is necessary because the regexp MatchData objects returned are strings.