grep using regular expression “and”

Question

我如何过滤掉包含canvasbench和tracing_mark_write的行，如下面的句子所示？

 canvasbench-16333 [003] ...1 87432.398788: tracing_mark_write: B|16333|performTraversals\n\

Answer 1

There is no AND operator in grep. But, you can simulate AND using grep -E option.

grep -E 'canvasbench.*tracing_mark_write|tracing_mark_write.*canvasbench' filename

And alternatively, you can use multiple grep command separated by pipe to simulate AND.

grep -E 'canvasbench' filename | grep -E 'tracing_mark_write'

Answer 2

Alternatively you can use sed:

sed -n '/canvasbench/{/tracing_mark_write/p}' input

which tries to match tracing_mark_write on lines matching canvasbench and prints lines matching both.