How to convert a string of numbers to an array of numbers?

Question

I have below string -

var a = "1,2,3,4";

when I do -

var b = a.split(',');

I get b as ["1", "2", "3", "4"]

can I do something to get b as [1, 2, 3, 4] ?

Answer 1

You can use Array.map to convert each element into a number.

var a = "1,2,3,4";

var b = a.split(',').map(function(item) {
    return parseInt(item, 10);
});

Check the Docs

---

Or more elegantly as pointed out by User: thg435

var b = a.split(',').map(Number);

Where Number() would do the rest:check here

---

Note: For older browsers that don't support map , you can add an implementation yourself like:

Array.prototype.map = Array.prototype.map || function(_x) {
    for(var o=[], i=0; i<this.length; i++) { 
        o[i] = _x(this[i]); 
    }
    return o;
};

Answer 2

My 2 cents for golfers:

b="1,2,3,4".split`,`.map(x=>+x)

backquote is string litteral so we can omit the parenthesis (because of the nature of split function) but it is equivalent to split(',') . The string is now an array, we just have to map each value with a function returning the integer of the string so x=>+x (which is even shorter than the Number function (5 chars instead of 6)) is equivalent to :

function(x){return parseInt(x,10)}// version from techfoobar
(x)=>{return parseInt(x)}         // lambda are shorter and parseInt default is 10
(x)=>{return +x}                  // diff. with parseInt in SO but + is better in this case
x=>+x                             // no multiple args, just 1 function call

I hope it is a bit more clear.

Answer 3

This is very simple.Such as:

["1", "2", "3", "4"].map(i=>Number(i))

you can run the demo.

 let result = ["1", "2", "3", "4"].map(i=>Number(i)); console.log(result);

Answer 4

Array.from() for details go to MDN

let a = "1,2,3,4";
let b = Array.from(a.split(','),Number);

or

let c = ["1", "2", "3", "4"].map(Number);

b and c is an array of numbers.

demonstration:

 let a = "1,2,3,4"; let b = Array.from(a.split(','),Number); let c = ["1", "2", "3", "4"].map(Number); console.log(`b: ${b}, c: ${c}`);

Answer 5

Map it to integers:

a.split(',').map(function(i){
    return parseInt(i, 10);
})

map looks at every array item, passes it to the function provided and returns an array with the return values of that function. map isn't available in old browsers, but most libraries like jQuery or underscore include a cross-browser version.

Or, if you prefer loops:

var res = a.split(",");
for (var i=0; i<res.length; i++)
{
    res[i] = parseInt(res[i], 10);
}

Answer 6

+string will try to change the string to a number. Then use Array.map function to change every element.

"1,2,3,4".split(',').map(function(el){ return +el;});

Answer 7

A more shorter solution: map and pass the arguments to Number :

 var a = "1,2,3,4"; var b = a.split(','); console.log(b); var c = b.map(Number); console.log(c);

Answer 8

一个班轮

Array.from(a.split(','), Number)

Answer 9

There's no need to use lambdas and/or give radix parameter to parseInt , just use parseFloat or Number instead.

Reasons:

1. It's working:

    var src = "1,2,5,4,3"; var ids = src.split(',').map(parseFloat); // [1, 2, 5, 4, 3] var obj = {1: ..., 3: ..., 4: ..., 7: ...}; var keys= Object.keys(obj); // ["1", "3", "4", "7"] var ids = keys.map(parseFloat); // [1, 3, 4, 7] var arr = ["1", 5, "7", 11]; var ints= arr.map(parseFloat); // [1, 5, 7, 11] ints[1] === "5" // false ints[1] === 5 // true ints[2] === "7" // false ints[2] === 7 // true

2. It's shorter.

3. It's a tiny bit quickier and takes advantage of cache, when parseInt -approach - doesn't :

    // execution time measure function // keep it simple, yeah? > var f = (function (arr, c, n, m) { var i,t,m,s=n(); for(i=0;i++<c;)t=arr.map(m); return n()-s }).bind(null, "2,4,6,8,0,9,7,5,3,1".split(','), 1000000, Date.now); > f(Number) // first launch, just warming-up cache > 3971 // nice =) > f(Number) > 3964 // still the same > f(function(e){return+e}) > 5132 // yup, just little bit slower > f(function(e){return+e}) > 5112 // second run... and ok. > f(parseFloat) > 3727 // little bit quicker than .map(Number) > f(parseFloat) > 3737 // all ok > f(function(e){return parseInt(e,10)}) > 21852 // awww, how adorable... > f(function(e){return parseInt(e)}) > 22928 // maybe, without '10'?.. nope. > f(function(e){return parseInt(e)}) > 22769 // second run... and nothing changes. > f(Number) > 3873 // and again > f(parseFloat) > 3583 // and again > f(function(e){return+e}) > 4967 // and again > f(function(e){return parseInt(e,10)}) > 21649 // dammit 'parseInt'! >_<

Notice: In Firefox parseInt works about 4 times faster, but still slower than others. In total: +e < Number < parseFloat < parseInt

Answer 10

As a variant you can use combiantion _.map and _.ary methods from the lodash library . Whole transformation will be a more compact. Here is example from the official documentation :

_.map(['6', '8', '10'], _.ary(parseInt, 1));
// → [6, 8, 10]

Answer 11

The underscore js way -

var a = "1,2,3,4",
  b = a.split(',');

//remove falsy/empty values from array after split
b = _.compact(b);
//then Convert array of string values into Integer
b = _.map(b, Number);

console.log('Log String to Int conversion @b =', b);

Answer 12

Matt Zeunert 的带有使用箭头功能的版本（ES6）

const nums = a.split(',').map(x => parseInt(x, 10));

Answer 13

This works amazing if you need to convert an array of strings to numbers.

const numbers = arr => arr.map(Number);
numbers(['1', '2', '3','4']);     // [1, 2, 3, 4]

Answer 14

Since all the answers allow NaN to be included, I thought I'd add that if you want to quickly cast an array of mixed values to numbers you can do.

var a = "1,2,3,4,foo,bar";

var b = a.split(',');

var result = b.map(_=>_|0) // Floors the number (32-bit signed integer) so this wont work if you need all 64 bits.

// or b.map(_=>_||0) if you know your array is just numbers but may include NaN.

Answer 15

You can use JSON.parse , adding brakets to format Array

 const a = "1,2,3,4"; const myArray = JSON.parse(`[${a}]`) console.log(myArray) console.info('pos 2 = ', myArray[2])

Answer 16

您可以在一行中将字符串数组转换为数字数组：

const arrayOfNumbers = arrayOfStrings.map(e => +e);

Answer 17

another way is combination of split and join

 var a = "1,2,3,4"; var b= Number(a.split(",").join("")) console.log(b); 

Answer 18

let ar = [ '682',    '874',    '906',    '11168',  '73714',
  '74377',  '74034',  '138860', '138891', '139161', '139562',
  '139733', '139560', '74049',  '139759', '139934', '140104',
  '141335', '141356', '141334', '141337', '141360', '141358',
  '141365', '141419', '143333', '151477', '147342', '141355',
  '167847', '192141', '196760', '191687', '197351', '197055',
  '198852', '198731', '198816', '199034', '200053', '199226',
  '217818', '200055', '222039', '230533', '230530', '231127',
  '222042', '231100', '236171', '236913', '236980', '237015',
  '237016', '237052', '237551', '237560', '237590', '237637',
  '237733', '237731', '237655', '238890', '238910', '238837',
  '238926', '238972', '238925', '239755', '239696', '239898',
  '240037', '239909', '240036', '240082', '240097', '240526',
  '240770', '678151', '678950', '678985'];
let arry=[]
ar.map(arr=>{
arry.push(parseInt(arr))
});

console.log(arry);

Answer 19

Use Array.from for this, Try this:

 let b = ["1", "2", "3", "4"]; b = Array.from(b,Number); console.log(b);

Answer 20

you can do:

b.map(num=>parseInt(num))