How to convert t[i][j] to pointer style reference

Question

For example t[i] is *(t+i)

How it will be for t[i][j] ?

In my opinion *(*(t+i)+j) but not sure.

Answer 1

Yes, what you have is correct. t[i][j] may be written as (t[i])[j] , so you may then apply the "1D" rule recursively.

Answer 2

You have to know how the data is stored in memory, as you want to operate on pointers. For 2-dimensional arrays there is no significant difference - the "rows" just tells how many "cells" the app should skip.

Let's assume for a while, that t is an integer, so when you have an array, which looks like this:

|3|4|5|

|6|5|4|

it will look, in fact like

|3|4|5|6|5|4|

as stored in memory. The array means that the program has to "skip" after 3rd value in array x[3][2] , then t[i][j] would look like *(*(t+i)+j)

Answer 3

Yes, you're right. t[i][j] is equivalent to *(*(t + i) + j) .